IPL 2019 Final: Rohit Sharma wins toss, elects to bat against CSK

Mumbai Indians have brought in Mitchell McClenaghan, replacing Jayant Yadav while CSK are unchanged.

Mumbai Indians skipper Rohit Sharma (Photo | AP)

HYDERABAD: Mumbai Indians skipper Rohit Sharma won the toss and elected to bat against Chennai Super Kings in the Indian Premier League title clash, here Sunday.

Mumbai Indians have brought in Mitchell McClenaghan, replacing Jayant Yadav while CSK are unchanged.

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Both the sides have won three titles each.

The @mipaltan Skipper Rohit Sharma wins the toss and elects to bat first against @ChennaiIPL.#IPLFinal #MIvCSK pic.twitter.com/807XBZROHo

— IndianPremierLeague (@IPL) May 12, 2019

Teams:

Chennai Super Kings: MS Dhoni (C), Faf du Plessis, Shane Watson, Suresh Raina, Ambati Rayudu, Dwayne Bravo, Ravindra Jadeja, Harbhajan Singh, Deepak Chahar, Shardul Thakur and Imran Tahir.

Mumbai Indians: Rohit Sharma(C), Quinton de Kock, Suryakumar Yadav, Ishan Kishan, Krunal Pandya, Hardik Pandya, Kieron Pollard, Rahul Chahar, Mitchell McClenaghan, Jasprit Bumrah and Lasith Malinga.