India wrestler Reetika Hooda  (File Photo)
Olympics

Wrestler Reetika Hooda loses Olympics freestyle quarter-final

The referee stopped the contest with 29 seconds left in the second round as Reetika gained a 10-point lead with the final score reading 12-2 in favour of the Indian.

PTI

PARIS: Indian wrestler Reetika Hooda lost a close quarter-final bout against Aiperi Medet Kyzy of Kyrgyzstan in the women's 76 kg freestyle category at the Paris Olympics on Saturday.

The wrestlers were locked 1-1 after six minutes of top-quality defensive wrestling but the Kyrgyz won having logged home the last equalising point as per rules.

Both wrestlers played a defensive game and the solitary point each was scored through passivity across the two periods.

Reetika will now wait for Kyzy to enter the final which will give her a shot at competing in the repechage round.

If she doesn't then India's Paris Games campaign will end with six medals and without a gold.

Earlier, Reetika displayed power and skill in equal measure while outclassing Bernadett Nagy of Hungary 12-2 in the pre-quarterfinals.

Dozens dead, 100 injured after fire rips through ski resort town in Switzerland

Gold missing from more artefacts in Sabarimala temple, stolen materials not fully recovered: SIT tells court

Indore water contamination: Locals claim 13 deaths, Mayor puts it at seven while CM confirms only four

Dense fog disrupts flight operations at Bhubaneswar, six flights diverted

First Vande Bharat sleeper train to run between Guwahati-Kolkata; PM Modi to flag off soon

SCROLL FOR NEXT